#include<bits/stdc++.h>
#define ff first
#define ss second
#define pb push_back
#define all(x) x.begin(), x.end()
#define nl '\n'
#define int long long
#define pii pair<int, int>
//#define ll long long
#define mod 1000000007 // 998244353 1000000007
using namespace std;
const int N = 2e5 + 5;
int a[N][26];
int n;
int x, y;
bool ok(int mid)
{
int r = a[mid - 1]['R' - 'A'], u = a[mid - 1]['U' - 'A'], l = a[mid - 1]['L' - 'A'], d = a[mid - 1]['D' - 'A'];
int tr = a[n - 1]['R' - 'A'], tu = a[n - 1]['U' - 'A'], tl = a[n - 1]['L' - 'A'], td = a[n - 1]['D' - 'A'];
int tx = tr - r - (tl - l), ty = tu - u - (td - d);
if((abs(x - tx) + abs(y - ty)) <= mid)
{
int k = mid - abs(x - tx) - abs(y - ty);
if(k % 2 == 0) return true;
}
for(int i = mid; i < n; i++)
{
r = a[i]['R' - 'A'] - a[i - mid]['R' - 'A'],
u = a[i]['U' - 'A'] - a[i - mid]['U' - 'A'],
l = a[i]['L' - 'A'] - a[i - mid]['L' - 'A'],
d = a[i]['D' - 'A'] - a[i - mid]['D' - 'A'];
tx = tr - r - (tl - l), ty = tu - u - (td - d);
if((abs(x - tx) + abs(y - ty)) <= mid)
{
int k = mid - abs(x - tx) - abs(y - ty);
if(k % 2 == 0) return true;
continue;
// cout << "r: " << r << " l: " << l << " d: " << d << " u: " << u << nl;
// cout << mid << " tx: " << tx << " ty: " << ty << nl;
// cout << (abs(x - tx) + abs(y - ty)) << nl;
}
}
return false;
}
void solve()
{
cin >> n;
string s;
cin >> s;
cin >> x >> y;
if(abs(x) > n or abs(y) > n)
{
cout << -1 << nl;
return;
}
for(int i = 0; i < n; i++)
{
a[i][s[i] - 'A']++;
if(i != 0)
{
a[i]['R' - 'A'] += a[i - 1]['R' - 'A'];
a[i]['L' - 'A'] += a[i - 1]['L' - 'A'];
a[i]['D' - 'A'] += a[i - 1]['D' - 'A'];
a[i]['U' - 'A'] += a[i - 1]['U' - 'A'];
}
}
int tx = (a[n - 1]['R' - 'A'] - a[n - 1]['L' - 'A']), ty = (a[n - 1]['U' - 'A'] - a[n - 1]['D' - 'A']);
if(tx == x and ty == y)
{
cout << 0 << nl;
return;
}
int l = 1, r = n;
int ans = 1e9;
while(l <= r)
{
int mid = (l + r)/2;
if(ok(mid))
{
ans = mid;
r = mid - 1;
}
else
{
l = mid + 1;
}
}
if(ans == 1e9)
{
cout << -1 << nl;
}
else
{
cout << ans << nl;
}
}
signed main()
{
ios_base::sync_with_stdio(false), cin.tie(nullptr);
int t = 1;
// cin >> t;
while(t--)
{
solve();
}
}
1209. Remove All Adjacent Duplicates in String II | 994. Rotting Oranges |
983. Minimum Cost For Tickets | 973. K Closest Points to Origin |
969. Pancake Sorting | 967. Numbers With Same Consecutive Differences |
957. Prison Cells After N Days | 946. Validate Stack Sequences |
921. Minimum Add to Make Parentheses Valid | 881. Boats to Save People |
497. Random Point in Non-overlapping Rectangles | 528. Random Pick with Weight |
470. Implement Rand10() Using Rand7() | 866. Prime Palindrome |
1516A - Tit for Tat | 622. Design Circular Queue |
814. Binary Tree Pruning | 791. Custom Sort String |
787. Cheapest Flights Within K Stops | 779. K-th Symbol in Grammar |
701. Insert into a Binary Search Tree | 429. N-ary Tree Level Order Traversal |
739. Daily Temperatures | 647. Palindromic Substrings |
583. Delete Operation for Two Strings | 518. Coin Change 2 |
516. Longest Palindromic Subsequence | 468. Validate IP Address |
450. Delete Node in a BST | 445. Add Two Numbers II |